14. Calculaiton of power required

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Once the MAXIMUM CHAIN PULL has been established, the following calculation for head shaft power requirements should be employed.

$Mt=P\frac{dp}{2}[kgm]$

$Mt=716.2\frac{N}{R}[kgm]$

Where:
$Mt$ = Torque (Kg m)
$N$ = Power CV.Hp or KW)
$R$ = Head Shaft RPM
$P$ = total chain pull
$dp$ = PCD of Drive sprockets (m)

From these two relationships it is concluded

$P\frac{dp}{2}[kgm]=716.2\frac{N}{R}$

From which is derived

$N=\frac{P.dp.R}{2.716.2}[CV] \quad alternatively \quad N=\frac{P.dp.R}{2.973.8}[KW]$

The useable power output to be established must take into account losses from reduction with chain and belt transmissions.

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14. Calculaiton of power required

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