14. Calculaiton of power required

Once the MAXIMUM CHAIN PULL has been established, the following calculation for head shaft power requirements should be employed.

    \[ Mt=P\frac{dp}{2}[kgm] \]

    \[ Mt=716.2\frac{N}{R}[kgm] \]

Mt = Torque (Kg m)
N = Power CV.Hp or KW)
R = Head Shaft RPM
P = total chain pull
dp = PCD of Drive sprockets (m)

From these two relationships it is concluded

    \[ P\frac{dp}{2}[kgm]=716.2\frac{N}{R} \]

From which is derived

    \[ N=\frac{P.dp.R}{2.716.2}[CV] \quad alternatively \quad N=\frac{P.dp.R}{2.973.8}[KW] \]

The useable power output to be established must take into account losses from reduction with chain and belt transmissions.